Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
858 views
in Trigonometry by (25.8k points)
closed by

Evaluate \(\sin\begin{Bmatrix}\frac{\pi}{2}-\left(\frac{-\pi}{3}\right)\end{Bmatrix}\)

1 Answer

+1 vote
by (27.7k points)
selected by
 
Best answer

\(\sin\left(\frac{\pi}{2}+\frac{\pi}{3}\right)\)

\(=\sin\left(\frac{5\pi}{6}\right)\)

\(=\sin\left(\pi-\frac{\pi}{6}\right)\)

\(=\sin\frac{\pi}{6}=\frac{1}{2}\)

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...