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Let ƒ : R – {3} → R – {1} be defined by f(x) = \(\frac{x-2}{x-3}.\) Let g : R → R be given as g(x) = 2x – 3. Then, the sum of all the values of x for which ƒ–1(x) + g–1(x) = \(\cfrac{13}2\) is equal to

(1) 7

(2) 2

(3) 5

(4) 3

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