​ Let y = y(x) be the solution of the differential equation xdy - ydx = ​√(x^2 - y^2) dx, x ≥ 1,

Question

Let y = y(x) be the solution of the differential equation xdy - ydx = \(\sqrt{(x^2-y^2)}dx, x \ge1,\) with y(1) = 0. If the area bounded by the line x = 1, x = e^π, y = 0 and y = y(x) is αe^2π + β, then the value of 10(α + β) is equal to ........

Answer 1

Answer is 4

xdy - ydx = \(\sqrt{x^2-y^2}\) dx