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Evaluate the following:

sec-1(sec \(\frac{5\pi}4\))

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Best answer

The value of sec\((\frac{5\pi}4)\) is -√2.

∴ The question becomes sec–1(–√2).

The range of principal value of sec–1is [0, π] -\(\{\frac{\pi} {2}\}\)

and sec\((\frac{3\pi}4)\) = -√2

∴ The principal value of sec–1(–√2) is \(\frac{3\pi}4.\)

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