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Prove the following results:

tan-1\(\frac 17\) + tan-1\(\frac{1}{13}\) = tan-1\(\frac 29\)

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Given:- tan-1(\(\frac 17\)) + tan-1(\(\frac{1}{13}\)) = tan-1(\(\frac 29\))

Take

LHS

 tan-1(\(\frac 17\)) + tan-1(\(\frac{1}{13}\))

We know that, Formula

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