Correct option is B.\(\frac{\sqrt3}2\)
We are given that,
sin-1x - cos-1x = \(\frac{\pi}6\).....(i)
We need to find the value of x.
By using the property of inverse trigonometry,
sin-1x + cos-1x = \(\frac{\pi}2\)
We can find the value of sin-1x in the terms of cos-1x.
⇒ sin-1x = \(\frac{\pi}2\) - cos-1x
Substituting the value of sin-1x in equation (i),