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The mean and variance of a binomial distribution are 4 and (4/3) respectively. Find P(X≥ 1).

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The mean and variance of a binomial distribution are 4 and (4/3) respectively. Find P(X≥ 1).

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1 Answer

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Best answer

Mean = np = 4

Variance = npq = 4/3

The probability \((X \geq 1)\) is

 

\(=\frac{728}{729}\)

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