Correct option is D. 0
We need to find the value of:

Since, cos\((2\pi-\frac{\pi}3)\) lies on IV Quadrant and cosine is positive in IV Quadrant.
cos\((2\pi-\frac{\pi}3)\) = - sin\(\frac{\pi}3\)
And since, sin\((2\pi-\frac{\pi}3)\) lies on IV Quadrant and sine is negative in IV Quadrant.
