Let P be the position of the kite and PR be the position of the string. Let QR = x and PR = y. Then from figure by applying Pythagoras theorem, we get
Differentiating the above equation with respect to time, we get
Now the kite is moving away horizontally at the rate of 52m/sec, so \(\frac{dx}{dt}\) = 52 m/sec, so the above equation becomes
So when the string is 130m, y = 130m equation (i) become,
Substituting the value of x and y in equation (ii), we get
Hence the rate at which the string is being paid out is 20m/sec