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Find two irrational numbers lying between 0.1 and 0.12.

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Let, a = 0.1 = 0.10 

And, b = 0.12 

We observe that in the second decimal place a has digit 0 and b has digit 2. Therefore a < b. So, if we consider irrational numbers 

x = 0.11011001100011… 

y = 0.111011110111110… 

We find that, 

a < x < y < b 

Hence, x and y are required irrational numbers.

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