If x = 3 and y = -1, find the values of each of the following using in identity:
(i) (9y2 - 4x2) (81y4 + 36x2y2 +16x4)
(ii) \((\frac{3}{x}-\frac{x}{3})\)\((\frac{x^2}{9}+\frac{9}{x^2}+1)\)
(iii) \((\frac{x}{7}+\frac{y}{3})\)\((\frac{x^2}{49}+\frac{y^2}{9}-\frac{xy}{21})\)
(iv) \((\frac{x}{4}-\frac{y}{3})\)\((\frac{x^2}{16}+\frac{xy}{12}+\frac{y^2}{9})\)
(v) \((\frac{5}{x}+5x)\)\((\frac{25}{x^2}-{25}+25x^2)\)