Find dy/dx, when x = 3at/(1 + t^2) and y = (3at^2)/(1+t^2)

Question

Find \(\cfrac{dy}{d\mathrm x} \), when 

x = \(\cfrac{3at}{1+t^2}\) and y = \(\cfrac{3\,at^2}{1+t^2}\)

Answer 1

as x = \(\cfrac{3at}{1+t^2}\)

Differentiating it with respect to t using quotient rule,

Differentiating it with respect to t using quotion rule

Dividing equation (2) by (1),