Given,
∠A = 120°
AB = AC
We have to find ∠B and ∠C:
We can observe that Δ ABC is an isosceles triangle since AB = AC
∠B = ∠C (Angle opposite to equal sides are equal) [i]
We know that,
Sum of angles in a triangle is equal to 180°
∠A + ∠B + ∠C = 180°
∠A + ∠B + ∠B = 180°
∠A + 2∠B = 180°
120° + 2∠B = 180°
2∠B = 180° – 120°
2∠B = 60°
∠B = 30°
∠B = ∠C = 30°