Consider the figure,
Given,
AB = AC
DB = DC
To find: Ratio
∠ABD =∠ACD
Now, ΔABC and ΔDBC are isosceles triangles
Since,
AB = AC
And,
DB = DC
Therefore,
∠ABC = ∠ACB and,
∠DBC = ∠DCB (Angle opposite equal sides)
Now, consider ∠ABD : ∠ACD
(∠ABC - ∠DBC) : (∠ACB - ∠DCB)
(∠ABC - ∠DBC) : (∠ABC - ∠DBC) [Since, ∠ABC = ∠ACB and ∠DBC = ∠DCB]
1: 1
Therefore,
∠ABD : ∠ACD = 1:1