Question

Two opposite angles of a parallelogram are (3x-2)°and (50-x)°.

Find the measure of each angle of the parallelogram.

Answer 1

Given, 

Two opposite angles of a parallelogram (3x - 2) and (50 – x) 

Opposite angles of a parallelogram are equal, 

3x – 2 = 50 – x 

4x = 52 ∘ 

x = 13 ∘ 

So, angles are 

3x – 2 = 3×13-2 = 37^∘ 

50 – x = 50 -13 = 37^∘ 

Sum of other two angles = 360 - 2×37 = 360 – 74 = 286^∘ 

So each angle will be = \(\frac{286}{2}\) = 143^∘