Question

The water bills (in rupees) of houses in a certain street for the period 1.1.98 to 31.3.98 are given below:

56, 43, 32, 38, 56, 24, 68, 85, 52, 47, 35, 58, 63, 74, 27, 84, 69, 35, 44, 75, 55, 30, 54, 65, 45, 67, 95, 72, 43, 65, 35, 59

Tabulate the data and present the data as a cumulative frequency table using 70 -79 as one of the class intervals.

Answer 1

The minimum bill is Rupees 24

And,

The maximum bill is Rupees 95

Range = Maximum bill – Minimum bill

= 95 – 24 = 71

Given,

Class interval is 70 - 79.

So,

Class size = 79 – 70

= 9

Therefore,

Number of classes = \(\frac{Range}{class \,size}\) = \(\frac{71}{9}\)

= 7.80 = 8

The cumulative frequency distribution table is as follows: