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Using factor theorem, factorize each of the following polynomial: 

x3 - 2x2 - x + 2

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Let, f (x) = x3 - 2x2 - x + 2

The factors of the constant term +2 are \(\pm\) 1, \(\pm\) 2

Putting x = 1, we have

f (1) = (1)3 – 2 (1)2 – (1) + 2

= 1 – 2 – 1 + 2

= 0

So, 

(x - 1) is a factor of f (x)

Let us now divide

f (x) = x3 - 2x2 - x + 2 by (x - 1) to get the other factors of f (x)

Using long division method, we get

x3 - 2x2 - x + 2 = (x - 1) (x2 - x - 2)

x2 - x - 2 = x2 - 2x + x - 2

= x (x - 2) + 1 (x - 2)

= (x + 1) (x - 2)

Hence, 

x3 - 2x2 - x + 2 = (x - 1) (x + 1) (x - 2)

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