Question

ABCD is a parallelogram in which diagonal AC bisects ∠BAD. If ∠BAC =35°, then ∠ABC = 

A. 70° 

B. 110° 

C. 90° 

D. 120°

Answer 1

Option : (B)

Given, 

ABCD is a parallelogram 

Diagonal AC bisects ∠BAD

∠BAC = 35° ∵∠A+∠B = 180° …………(i) 

[angle sum property of quadrilateral] 

∠A = 2∠BAC = 2×35° = 70° 

Putting value of ∠A in equation (i) 

= 70°+∠B = 180° 

= ∠B = 180°- 70° = 110° 

∠ABC = 110°