Given, Height of right circular cylinder = 10.5 m
And 3(area of both circular ends) = 2(curved surface area of cylinder)
= 3\(\times\)πr2 = 2\(\times\)2πrh = 6πr2 = 4πrh
= 3r = 2h
or r = \(\cfrac23\)h = \(\cfrac23\times10.5\) = 7 m
So, volume of cylinder = πr2h = \(\cfrac{22}7\times
\) 49 \(\times\) 10.5
= 1617 m3