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The height of a right circular cylinder is 10.5 m. Three times the sum of the areas of its two circular faces is twice the area of the curved surface. Find the volume of the cylinder.

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Given, Height of right circular cylinder = 10.5 m

And 3(area of both circular ends) = 2(curved surface area of cylinder)

= 3\(\times\)πr2 = 2\(\times\)2πrh = 6πr2 = 4πrh

= 3r = 2h

or  r = \(\cfrac23\)h = \(\cfrac23\times10.5\) = 7 m

So, volume of cylinder = πr2h = \(\cfrac{22}7\times \) 49 \(\times\) 10.5

= 1617 m3

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