Given:
number \(\frac{2\sqrt{45}+3\sqrt{20}}{2\sqrt5}\)
To find:
Whether the given number is rational or irrational
Solution:
Factorize 45 and 20.
⇒ \(\frac{2\sqrt{45}+3\sqrt{20}}{2\sqrt5}\) = \(\frac{2\sqrt{3\times 3\times 5}+3\sqrt{2\times 2\times 5}}{2\sqrt5}\)
⇒ \(\frac{2\sqrt{3^2\times 5}+3\sqrt{2^2\times 5}}{2\sqrt5}\)
⇒ \(\frac{2\times 3\sqrt{5}+3\times 2\sqrt{5}}{2\sqrt5}\)
⇒ \(\frac{2\sqrt{5}(3+3)}{2\sqrt5}\)
⇒ 3 + 3 = 6
We know that a rational number is defined as the number which can be written in the form of p/q.
As 6 can be written as 6/1.
So 6 is a rational number.
The given number after simplification gives a rational number.