Question

The chord of a circle is equal to its radius. The angle substended by this chord at the minor arc of the circle is

A. 60° 

B. 75° 

C. 120° 

D. 150°

Answer 1

Option : (D)

Let AB be the chord of circle equal to radius r 

OA = OB = r (Radii) 

Therefore, 

OA = OB = AB 

OBC is equilateral triangle 

Each angle = 60° 

Hence, 

Angle surrounded by AB at minor arc = \(\frac{1}{2}\)(Reflex \(\times\) ∠AOD) 

= \(\frac{1}{2}\)(360° – 60°) 

= 150°