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Find the condition that the zeros of the polynomial f(x) = x3 + 3px2 + 3qx + r may be in A.P.

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Let α = a - d, β = a and y = a + d are the zeros of the given polynomial.

Sum of the zeros

Since α is the zero of the polynomial, therefore f(a) = 0

⇒ f(a) = a3 + 3pa2 + 3qa + r = 0

⇒ a3 + 3pa2 + 3qa + r = 0

On substituting a = - p, we get 

⇒ -p3 + 3p3 - 3pq + r = 0

⇒ 2p3 - 3pq + r = 0

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