(1) Draw a line segment BC = 7cm.
Using a protractor,
Draw ∠CBD = 60°.
Join and extend BD.
(2) Taking B as the center and radius = 12cm,
Draw an arc,
Intersecting extended BD at point P.
Join PC.
(3) Taking P as the center and radius greater than \(\frac{PC}{2}\),
Draw arcs on each side of PC.
Now,
Taking C as the center and same radius, draw arcs, intersecting the previous arcs at points Q and R.
Join and extend QR.
Extended QR intersects line segment DB at point A.
Join AC.
(4) ∆ABC is the required triangle.
