Question

The path of a train A is given by the equation 3x + 4y – 12 = 0 and the path of another train B is given by the equation 6x + 8y – 48 = 0. Represent this situation graphically.

Answer 1

Given equations are 3x + 4y – 12 = 0 and 6x + 8y – 48 = 0

Let us plot the given equations.

For this we will need some points to plot for the equation.

3x + 4y - 12 = 0

4y = 12 - 3x

Now let us take random values of x and obtain the corresponding values of y by putting in the equation. at x = 0, 4y = 12 - 3x 04y = 12y = 3

Now at y = 0, 3x + 4x 0 = 123x = 12x = 4

So we have two points for the equation 3x + 4y - 12 = 0 and those are (0, 3) and (4, 0)

6x + 8y - 48 = 0

Now let us find points for this equation at x = 0,6x 0 + 8y = 488y = 48y = 6 at y = 0,6x + 8x 0 = 486x = 48x = 8

So we have two points for the equation 6 x + 8 y - 48 = 0 and those are (8, 0) and (0, 6)3x + 4y – 12 = 0 passes through (4, 0) and (0, 3)

6x + 8y – 48 = 0 passes through (8, 0) and (0, 6)