Here,
the maximum frequency is 142, the corresponding class interval 165.5-168.5 is modal class
l=165.5, h=3, f=142, f1=118, f2 =127
Mode = l + \(\frac{f-f_1}{2f-f_1-f_2}\times h\)
\(=165.5+\frac{142-118}{2\times142-118-127}\times3\)
\(=18+\frac{72}{39}=165.5+1.85\)
=167.35 cm