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ΔABC ~ ΔDEF such that ar (ΔABC) = 4 ar (ΔPQR). If BC =12 cm, then QR =

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ΔABC ~ ΔDEF such that ar (ΔABC) = 4 ar (ΔPQR). If BC =12 cm, then QR =

A. 9 cm 

B. 10 cm 

C. 6 cm 

D. 8 cm

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Given ar (ΔABC) ~ ar (PQR) such that ar (ΔABC) = 4 ar (ΔPQR) and BC = 12 cm 

We know that ratio of areas of two similar triangles is equal to the ratio of squares of their corresponding sides.

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