The given equation is 3x-Kx+4 =0 .
This is the form of ax^2+bx+c=0 , where a=3 , b= -k and c =4 .
D= (b^2-4ac)
D= k^2 -4×3×4
D= k^2-48
For real roots, we must have
D=0
K^2-48=0
K^2= 48
K = ±√48
K = ±4√3
Hence, 4√3 and -4√3 are the required values of k.
