Let y = x(\(\frac{1}{x}\)).
Take antilog on both sides,
⇒ In y = \(\frac{1}{x}\) \(\times\) In x
Let us differentiate and find f’(x) = 0
But In x is not defined at x = 0
f(e) = e\(\frac{1}{e}\)
Therefore,
Minima occur at x = e.
So,
f(e) = e\(\frac{1}{e}\) is the minimum value of this function.