To find area bounded by
X = y2 …(i)
And X = 3 – 2y2 …(ii)
On solving the equation (i) and (ii),
y2 = 3 – 2y2
Or 3y2 = 3
Or y = \(\pm\)1
When y = 1 then x = 1 and when y = – 1 then x = 1
Equation (i) represents an upward parabola with vertex (0, 0) and axis – y.
Equation (ii) represents a parabola with vertex (3, 0) and axis as x – axis.
They intersect at A (1, – 1) and C (1, 1)
These are shown in the graph below: -

Required area = Region OABCO
= 2 Region OBCO
= 2[Region ODCO + Region BDCB]

The area bounded by the curves x = y2 and x = 3 – 2y2 is 4 sq. units.