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Evaluate the following integrals :

\(\int\frac{e^{x-1}+x^{e-1}}{e^x+x^e}\)dx

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Best answer

Multiplying and dividing the numerator by e we get the given as

⇒ \(\frac{1}{e}\)\(\int\frac{e^{x-1}+x^{e-1}}{e^x+x^6}\)dx  …(1)

Assume,

ex + xe = t 

⇒ d(ex + xe )= dt 

⇒ ex + exe-1 = dt 

Substituting t and dt in equation 1 we get 

⇒ \(\frac{1}{e}\int\frac{dt}{t}\)

= ln|t| + c 

But,

t = ex + xe 

∴ ln| ex + xe | + c.

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