Given equation, y = emx
On differentiating the above equation with respect to x we get
\(\frac{dy}{dx}\) = memx
But y = emx
\(\therefore \frac{dy}{dx} =\) my
Now we have, y = emx
Applying log on both sides, we get,
log y = mx
which gives m = \(\frac{\text{log y}}{\text{x}}\)
So, putting this value of m in \(\frac{dy}{dx} = \) my we get

Hence, \(x\frac{dy}{dx} = \) y log y is the differential equation corresponding to y = emx.