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Solve the following initial value problem:

2x\(\frac{\text{dy}}{\text{dx}}=\) 3y, y(1) = 2

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Given differential equation 2x\(\frac{\text{dy}}{\text{dx}}=\) 3y

Find: Find the general solution of this differential equation.

Put C =4 in equation (i)

y2 = x34

Hence, y2 = 4x3

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