Solve the following initial value problem: dy/dx = 1 + x + x^2 + xy^2 when y = 0, x = 0

Question

Solve the following initial value problem:

\(\frac{\text{dy}}{\text{dx}}=\) 1 + x + y² + xy² when y = 0, x = 0

Answer 1

Given:  \(\frac{\text{dy}}{\text{dx}}=\) 1 + x + y² + xy²

Putting the value of C in equation (i) we get.