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Can a vector have direction angles 45° , 60° , 120°.

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We know that, If l, m, n are the direction cosine of a vector and α, β, γ are the direction angle, then

– l = cosα, m = cosβ, n = cosγ

And, l2 + m2 + n2 = 1 …… (i)

∴ l = cos45°, m = cos60°, n = cos120°

l = \(\cfrac 1{\sqrt2}\), m = \(\cfrac12\), n = \(-\cfrac12\)

Now, substituting l, m, n in equation (i), we get -

⇒ L.H.S = R.H.S

∴ A vector can have direction angles 45° , 60° , 120°.

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