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Prove the following trigonometric identities: (secA+tanA-1)(secA-tanA+1) = 2tanA

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Prove the following trigonometric identities:

(secA+tanA-1)(secA-tanA+1) = 2tanA

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(secA+tanA-1)(secA-tanA+1)

= [secA+tanA-(sec2A+tan2A)][secA-tanA+(sec2A-tan2A)]

= 2tanA

Hence Proved.

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