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Prove the following trigonometric identities: cot^2A(secA-1)/1+sinA=sec^2A(1-sinA/1+secA)

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Prove the following trigonometric identities:

\(\frac{cot^2A(secA-1)}{1+sinA}\) = sec2A \((\frac{1-sinA}{1+secA})\)

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Best answer

\(\frac{cot^2A(secA-1)}{1+sinA}\)

From (1) and (2) we get 

LHS = RHS 

Hence Proved.

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