Given:
radius of cylinder (r) = \(\frac{20}2\) = 10 cm
Height of cylinder (h1) = 2.5 m
Height of cone (h2) = 7.5 m
Let l be slant height of cone
l = \(\sqrt{r^2 + h^2}\)
⇒ l = \(\sqrt{10^2 + 7.5^2}\)
⇒ l = 12.5 m
Volume of cylinder (V1) = πr2h
⇒ V1 = π r(10)2(2.5) ……….. (1)
Volume of cone (V2) = \(\frac{1}3\) πr2h
= \(\frac{1}3\) π(10)2 (7.5) …………. (2)
Total capacity of tent = (1) + (2)
V = V1 + V2
⇒ V = π(10)2(2.5) + \(\frac{1}3\) π(10)2 (7.5)
⇒ V = 250π + 250π
⇒ V = 500 π m3
∴Total capacity of tent = 500 π m3
