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+1 vote
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in Motion in a Straight Line by (33.8k points)
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A car of mass 1000 kg starts from rest at t = 0 and under goes acceleration as shown in figure.

1. Draw the corresponding velocity-time graph. 

2. What is the retarding force acting on the car?

3. What is the total distance travelled by the car during t = 0 to t = 4 sec.

1 Answer

+1 vote
by (35.6k points)
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Best answer

1.

2. Retarding acceleration, a = -3m/s2 

∴ Retarding force F = ma 

= 1000 × 3 

= 3000N. 

3. Area of velocity time gives distance. 

∴ Area = \(\frac{1}{2}\)bh = \(\frac{1}{2}\)× 4 × 6 

Distance = 12m.

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