Question

Calculate the mole fraction of NaOH in a solution containing 20 g of NaOH per 360 g of water.

Answer 1

Number of moles of NaoH = \(\frac{20g}{40\,g\,mol^{-1}}\) = 0.5

Number of moles of water = \(\frac{360g}{18\,g\,mol^{-1}}\) = 20

Total number of moles = 20.5

mole fraction of NoaH = \(\frac{0.5}{20.5}\) = 0.0244