Question

An object is projected with velocity U at an angle θ to the horizontal.

1. Obtain a mathematical expression for the range in the horizontal plane.

2. What are the conditions to obtain maximum horizontal range?

3. Find the maximum height of the object when its path makes an angle of 30° with the horizontal (velocity of projection = 8 ms^-1)

Answer 1

1. If we neglect the air resistance, the horizontal velocity (ucosθ) of projectile will be a constant.

Hence the horizontal distance (R) can be found as R = horizontal velocity × time of flight

2. when θ = 45° we get maximum horizontal range

3. Height H