Question

Raju increased the speed of moving mass ‘50 kg’ from 2 m/s to 4m/s.

1. How much force will be required, if velocity change takes place with in 0.2 sec?

2. How much work is done by Raju?

Answer 1

1. F = mass × acceleration

= 50 × (4−2)/0.2

= 500N.

2. w = \(\frac{1}{2}\)mv² – 12mu².

=\(\frac{1}{2}50\) (4² – 2²)

= 300 J.