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Raju dropped a rubber ball of mass m from a height h to the ground. He observed that the ball rebounds vertically and along the same line to a height h1, which is less than h.

1. Is it an elastic or inelastic collision?

2. Find the velocity with which it strikes the ground?

3. If it is replaced by a solid aluminium ball, then what happens to the height of rebound?

4. If the rubber ball is allowed to fall on a spring placed on the ground then what change will Raju notice in the height of rebound?

1 Answer

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1. Inelastic collision.

2. The velocity with which ball strikes the ground,

v2 = u2 + 2as

v2 = 0 + 2g × h

v = \(\sqrt {2gh}\).

3. Height of rebound decreases.

4. Height of rebound depends on the state of potential energy stored in the spring. If ball falls on a compressed spring, the height of rebound increases due to potential energy given by the spring to bail.

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