Question

A toy gun, with a spring compresser 3cm is used to project a stone of mass 50gm to a height of 10m.

1. What is the potential energy of spring.

2. How much it should be compressed to throw the stone to a height 5m.

3. Find out the physical constant associated with the spring.

Answer 1

1. PE of the spring = PE of the mass at the height h

= mgh = 0.050 × 9.8 × 10

= 5 × 9.8 = 4.9J

2. \(\frac{1}{2}\)kx₁² = mgh₁

\(\frac{1}{2}\)kx₂² = mgh₂

3. physical constant associated with the spring constant
\(\frac{1}{2}\)kx² = mgh