Question

A graph paper is fitted on a board as shown in figure. Near to the graph paper a spring is placed. A pencil is attached to the end of the spring as shown in figure. The pencil is free to move on the graph paper. A stone of mass 50 gm is placed 1m above the spring. [Spring constant k = 98N/m]

1. The energy possessed by the stone due to its height is called_______

2. If this stone falls on the spring, find the length of mark that produced on the graph paper due to pencil [The change in P E of stone due to compression may be negleted]

3. What will happen to the length of mark, if spring having smaller spring constant is used? Justify.

Answer 1

1. Potential energy.

2. \(\frac{1}{2}\)kx² = mg

\(\frac{1}{2}\) × 98 × x² = 50 × 10^-3 × 9.8 × 1

x² = 100 × 10⁴

x = 10cm.

3. The length of mark will be decreased. Compression of spring depends on spring constant.