Question

What will be the minimum pressure required to compress 500 dm³ of air at 1 bar to 200 dm³ at 30 °C?

Answer 1

p₁ = 1 bar p = ? 

V₁ = 500 dm³  V₂ = 200 dm³

Temperature remains constant.

According to Boyle’s law,

p₁V₁ = p₂V₂

Or p₂ = \(\frac{p_2V_2}{V_2}\) 

p₂ = \(\frac{1\ bar\times500\ dm^3}{200\ dm^3}\) = 2.5 bar