Question

The equilibrium constant for the reaction is 10. Calculate the value of ∆G ; Given R = 8 J K^-1 mol^-1 ; T = 300 K.

Answer 1

 ∆G^θ = -2.303 RT log K

Here, R = 8.0 JK^-1 mol^-1 ; T = 300K ; K = 10

 ∆G^θ  = -2.303 x 8 JK^-1 mol^-1 x 300 K x log10

         = -5527 J mol^-1

          = -5.527 kJ mol^-1