Question

Calculate the [H⁺] in the following biological fluids whose pH are given in brackets. 

(i) Human muscle fluid (6.83) 

(ii) Human stomach fluid (1.22) 

(iii) Human blood (7.38) 

(iv) Human saliva (6.4)

Answer 1

(i) pH =-log[H⁺] = 6.83 

log[H⁺] = – 6.83 

[H⁺] = antilog (- 6.83) = 1.48 × 10^-7 mol L^-1 

(ii) [H⁺] = antilog (- 1.22) = 6.03 × 10^-2 mol L^{​​​​​​​-1}

(iii) [H⁺] = antilog (- 7.38) = 4.17 × 10^-8mol L^{​​​​​​​-1} 

(iv) [H⁺] = antilog (- 6.4) = 3.98 × 10^-7 mol L^-1