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in Trigonometry by (28.9k points)
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A tower stands vertically on the ground. From a point on the ground, 20 m away from the foot of the tower, the angle of elevation of the top the tower is 60°. What is the height of the tower?

1 Answer

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Best answer

Let the height of the tower = h (m)

In ∆ABC, 

tan60° = \(\frac{AB}{BC}\)

\(\sqrt3\) = \(\frac{h}{20}\)

h = 20√3 m 

Therefore height of the tower is 20√3 m

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