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in Indefinite Integral by (28.4k points)
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If ∫ 1/((x+2)(x2+1))dx a log |1 + x2 +b tan–1x + 1/5log|x+2| + C, then

A. a = \(-\frac{1}{10}\), b = \(-\frac{2}{5}\)

B. a = \(\frac{1}{10}\), b = \(-\frac{2}{5}\)

C. a = \(-\frac{1}{10}\), b = \(\frac{2}{5}\)

D. a = \(\frac{1}{10}\), b = \(\frac{2}{5}\)

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