If ∫ 1/((x+2)(x2+1))dx a log |1 + x2 +b tan–1x + 1/5log|x+2| + C, then
A. a = \(-\frac{1}{10}\), b = \(-\frac{2}{5}\)
B. a = \(\frac{1}{10}\), b = \(-\frac{2}{5}\)
C. a = \(-\frac{1}{10}\), b = \(\frac{2}{5}\)
D. a = \(\frac{1}{10}\), b = \(\frac{2}{5}\)