∫ cos5x/sinx dx
To solve this type of integration we have to,
let cosx either sinx = t then manuplate them
Let sin x =t then cosx dx = dt
Also apply the formula of,
(sin2t + cos2t = 1)

= log |t| + t4/4 - t2
= log |sin x| + sin4x/4 - sin2x (By putting t = sin x)